Question

What is the 38th Sum of an AP series 10,7,4...​

Answer 1

Answer:

here, a = 10

         d= 7-10

            = -3

        n = 38

        aₙ = a₃₈

now 38 th term of ap = a₃₈ = a + (n-1) d

                                            =  10 + ( 38 - 1) -3

                                            = 10 + 37(3)

                                            = 10 + 111

                                            = 121

Answer 2

Answer:

S38 = -1919

Step-by-step explanation:

here, a=10,d=7-10=-3, n=38. now,

$s_{38} = \frac{38}{2}( 2 \times 10 + (38 - 1)( - 3) \\ = > s_{38} = 19(10 - 111) \\ = > s_{38} = - 1919$

hope this helps.

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