What is the 4rth term from the end of the AP -11, -8, -5 ...........49
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Answer:
4th term from last = 40
Step-by-step explanation:
In the given AP
a = -11 , d = -8 -(-11) = 3 ,
d = 3
Last term (tn) = 49
Tn = a + (n-1)d ...........(1)
49 = -11 + (n-1) 3
60 = 3n - 3
n = 21
Therefore there are 21 terms
4th term from the end is the 18th term from start
From eqn (1)
t18 = -11 + (18-1) 3
= -11 + 51
= 40
t18 = 40
4th term from last = 40
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