what is the 4th term of the AP where 3rd term and common difference are 15 and -3 respectively
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Step-by-step explanation:
GIven: 3rd term = 15
d= -3
3rd term = a + 2d
15 = a + 2 ( -3)
15 = a - 6
a = 21
Hence, 4th term = a + 3d
= 21 + 3 (-3)
= 12
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