Question

what is the 50th term of a sequence 13, 7, 1 ...

Answer 1

Answer:

series is in AP

d= 7-13 = 1-7 = -6

First term a=13

We have to find out 50 th term

T50 = a+(n-1)d

=13+(50-1)*-6

= 13+49*-6

= 13-294

= -281

The 50th term is -281

Answer 2

Given,

The sequence: 13, 7, 1

To Find,

The 50th term =?

Solution,

We can solve the question as follows:

It is given that we have to find the 50th term of the sequence 13, 7, 1.

The given sequence is in arithmetic progression since the difference between any two consecutive terms is a constant.

$7 - 13 = -6$

$1 - 9 = -6$

Now,

The nth term of an A.P. is given as:

$T_{n} = a + ( n - 1)d$

Where,

$a = First\: term$

$n = nth\: term$

$d = Common\: difference$

In the given A.P.,

$a = 13$

$n = 50$

$d = -6$

Substituting the values in the above formula,

$T_{50} = 13 + (50 - 1)(-6)$

     $= 13 + 49*(-6)$

     $= 13 - 294$

     $= -281$

Hence, the 50th term of the sequence is -281.