What is the 5th term from the end of the ap 2, 7, 12 ...., 47?
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Step-by-step explanation:
a= t1=7
t2=12
d= 5
tn=47
n=?
tn= a+(n-1)d
47= 7+ 5n-5
45/5=n
n=9
5th term from the end = 9-5= 4
t4= 7+15
t4= 22
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