Question

What is the 63rd
term of the following arithmetic sequence?
8, 14, 20, 26, …

Answer 1

Heya!

HERE IS YOUR ANSWER:

a= 8
a2= 14
d= 14-8= 6

a63= a+62d
= 8+ 62(6)
= 8+ 372
= 380

63rd term is 380

Answer 2

Given,

$a = 8 \\ \\ d = a_{2} - a_{1} \\ d = 14 - 8 \\ d = 6 \\ \\ n = 63$

We know that,

$a_{n} = a + (n - 1)d$

Substituting the values we get,

$a_{63} = 8 + (63 - 1)6 \\ \\ a_{63} = 8 + 62(6) \\ \\ a_{63} = 8 + 372 \\ \\ a_{63} = 380$

If any doubt, please ask ;)