Question

What is the 99th term of the A.P. 2, 2, 2, ... ?​

Answer 1

Answer:

I think answer would be n = -1

Answer 2

Therefore the 99th term is=2

Step-by-step explanation:

A.P is a sequence of numbers in which the difference between two consecutive terms is always constant.

The first term of the sequence is denoted by a

and common difference is denoted by r

Here first term (a) = 2

and common difference r= second term - first term

                                          = 2-2

                                          =0

Nth term of the sequence/ series is denoted by $T_n$

And $T_n = a+ (n-1)r$

Therefore the 99th term is $T_{99} = 2+(99-1)0$ =2