Question

What is the (a) highest; (b) lowest total resistance that can be obtained by
combination of four coils of resistance​

Answer 1

Answer:Highest resistance can be obtained from series connection

Rs=R1 + R2 + R3 + R4

Least resistance can be obtained from parallel connection

1/Rp=1/R1+1/R2+1/R3+1/R4

Answer 2

Answer:

lets R1=4Ω, R2=8Ω, R3=12Ω, R4=24Ω

highest resistance(Rs)= R1+R2+R3+R4

                                     = 4+8+12+24

                                      = 98Ω

Lowest resistance(1/Rp)= 1/R1+ 1/R2+ 1/R3 + 1/R4

                                       = 1/4 + 1/8 + 1/12 + 1/24

                                       = 6+3+2+1/24

                                       = 12/24

                                 1/Rp= 1/2

                                    Rp= 2Ω

Explanation:

hope it would be helpful!!!!