Question

What is the abscissa of (10,-2)

Answer 1

Answer:

10 because abscissa is x axis and x is always first then y

Answer 2

Step-by-step explanation:

Answer

AnswerOpen in answr app

AnswerOpen in answr appOpen_in_app

AnswerOpen in answr appOpen_in_appGiven

AnswerOpen in answr appOpen_in_appGiven x

AnswerOpen in answr appOpen_in_appGiven x 1

AnswerOpen in answr appOpen_in_appGiven x 1

AnswerOpen in answr appOpen_in_appGiven x 1 =10y

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =y

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2 =2y

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2 =2y 2

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2 =2y 2

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2 =2y 2 =−3

AnswerOpen in answr appOpen_in_appGiven x 1 =10y 1 =yx 2 =2y 2 =−3Distance d= (x 1 −x 2 ) 2 +(y 1 −y 2)2

−x 2 ) 2 +(y 1 −y 2)2

−x 2 ) 2 +(y 1 −y 2)2

−x 2 ) 2 +(y 1 −y 2)2 Or d 2

−x 2 ) 2 +(y 1 −y 2)2 Or d 2 =(x 1 −x 2 ) 2 +(y 1 −y 2 ) 2

100=(10−2)

100=(10−2) 2

100=(10−2) 2 +(y+3)

100=(10−2) 2 +(y+3) 2

100=(10−2) 2 +(y+3) 2

100=(10−2) 2 +(y+3) 2 (y+3)

100=(10−2) 2 +(y+3) 2 (y+3) 2

100=(10−2) 2 +(y+3) 2 (y+3) 2 =100−64

100=(10−2) 2 +(y+3) 2 (y+3) 2 =100−64(y+3)

100=(10−2) 2 +(y+3) 2 (y+3) 2 =100−64(y+3) 2

100=(10−2) 2 +(y+3) 2 (y+3) 2 =100−64(y+3) 2 =36

100=(10−2) 2 +(y+3) 2 (y+3) 2 =100−64(y+3) 2 =36y+3=6⇒y=3

100=(10−2) 2 +(y+3) 2 (y+3) 2 =100−64(y+3) 2 =36y+3=6⇒y=3y+3=−6⇒y=−9