Question

What is the absolute temperature of normal melting point of sulphur as read by thermometers A and B ?​

Answer 1

Triple point of water, T = 273.16 K.

At this temperature, pressure in thermometer A, PA = 1.250 × 105 Pa

Let T1 be the normal melting point of sulphur.

At this temperature, pressure in thermometer A, P1 = 1.797 x 105 Pa

According to Charles’ law, we have the relation:

(PA/T) = (P1/T1)

Therefore, T1 = (P1T)/ (PA)

= (1.797 x 105) x 273.16)/ (1.250 × 105)

= 392.69 K

Therefore, the absolute temperature of the normal melting point of sulphur as thermometer A is 392.69 K.

At triple point 273.16 K, the pressure in thermometer B, PB = (0.200 × 105) Pa

At temperature T1, the pressure in thermometer B, P2 = (0.287 × 105) Pa

According to Charles’ law, we can write the relation:

(PB/T) = (P1/T1)

= (0.200 x 105)/ (273.16) = (0.287 x 105)/ (T1)

Therefore T1 = ((0.287 x 105)/ (0.200 x 105)) x (273.16)

Therefore, the absolute temperature of the normal melting point of sulphur as read by thermometer B is 391.98 K.

Answer 2

Answer:

Therefore, the absolute temperature of the normal melting point of sulphur as thermometer A is 392.69 K. Therefore, the absolute temperature of the normal melting point of sulphur as read by thermometer B is 391.98 K.