Question

What is the acceleration due to gravity 3200 km from earth surface

Answer 1

Answer:

Assume-

     h= 3200km = 3200000m = 3.2 x10^6

     R= 6400km = 6400000m = 6.4 x 10^6

     g= 9.8m/s^2

We know that-

           g'= g[R^2/(R+h)^2]

              = 9.8(40.96 x 10^12/92.16 x 10^12)

              = 9.8 x 4/9

              = 4.355m/s^2 ~ 4.4m/s^2

Thus, value of g at a place 3200km above surface of the earth is 4.4m/s^2

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