Question

what is the acceleration due to gravity on the top of Mount Everest whose height is 8848 metres if acceleration due to gravity on the surface of the Earth is 9.8 metre per second square​

Answer 1

Answer:

9.77 m/s²

Explanation:

g = kM/R² , KM = gR²

g' = kM/(R+8.848)²

g' = gR²/(R+8.848)²

g' = gR²/(R+8.848)² , R = 7000km.

g' = g(7000/7008.848)²

g' = g(7000/7008.848)²

g' = 0.9975g

g' = 9.77 m/s²