what is the acceleration of a ball of mass 300g if force of 6N is applied on it
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Answer:
20m/s^2
Explanation:
Force(F) = 6 N
Acceleration (a) = ?
Mass(m) = 300g = 300/1000 = 0.3 Kg
Now,
F = m × a
6 = 0.3 × a
a = 6/0.3
a = 60/3
a = 20 m/s^2
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