Question

What is the acceleration of a ball traveling horizontally with an initial velocity of 20 meters/second and, 2.0 seconds later, a velocity of 30 meters/second?

Answer 1

Answer:

acceleration = change in velocity / time

a = v-u/t

a = 20-30/2

a = -10/2

a = -5m/s

hope it helps you

please mark my answer as brainlist....

Answer 2

Answer:

Average acceleration of the ball is 5 m/ sec^2.

Explanation:

Given,

initial velocity at t = 0 sec : (u) = 20 m/sec

Final velocity at t = 2 sec : (v) = 30 m/sec

we have to find average acceleration (a avg) of the body during this time interval from 0 to 2 sec.

We know that :

average acceleration is rate of change of velocity

so,

average acceleration =

(final velocity - initial velocity)/ Time

a avg = ∆v / ∆t * just a fancy writing.

= (30 - 20) m / (2-0) sec^2

= 10 m / 2 sec^2 *always

= 5 m / sec^2. maintain units.