Question

what is the acceleration of a car started from rest and acquired a velocity of 40 m/s in 8 seconds​

Answer 1

Explanation:

Given that,

Intial velocity u=0m/s

Final velocity v=54km/h=54×

18

5

=15m/s

Time t=2min=120s

Now, put the value in equation of motion

The acceleration is

v=u+at

a=

t

v−u

a=

120

15−0

a=o.125m/s

2

Now, again from equation of motion

The distance is

s=ut+

2

1

at

2

s=0+

2

1

×0.125×120×120

s=900m

Hence, the acceleration is 0.125m/s

2

and distance is 900m

Answer 2

Answer:

acceleration = 5 m/s

Explanation:

u = 0

v = 40m/s

t = 8 seconds

a= v-u /t

a = 40-0/8

a= 5 m/s