Question

what is the acceleration of a car that started from rest and acquired velocity of 60 m/s 8 s?​

Answer 1

v=u+at
Given,
u(initial velocity =Om/s
v(final vocity =60m/s
t(time=8 seconds
a=?
hence putting the values
60=0+8a
we have 8a=60
hence a=60/8
a=7.5m/s^2

Answer 2

Answer:

7.5 m/s^2

Explanation:

a = v-u/t

a = 60-0/8

a = 7.5 m/s^2