Question

what is the acceleration of a rocket driver sled that travels 360 metre in 8.3 seconds starting at 22 metre per second ​

Answer 1

Answer:

5.150 m/s²

Explanation:

Initial velocity = u = 22 m/s

Total distance = s = 360m

Time taken = t = 8.3 seconds

According to the formula:

S=ut+½at²

360=22×8.3 + ½×a×(8.3)²

360 = 182.6 +½×a×68.89

177.4 = ½×a×68.89

177.4 = 34.445 a

a = 177.4/34.445

a = 5.150 m/s²