Physics, asked by mayanglambamrohit7, 4 hours ago

What is the acceleration of an object if its displacement is s, equals, 4, t, minus, 5, t, squared,s=4t−5t
2
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Answers

Answered by ankitsahu032004
1

Explanation:

here displacement is given...

differentiation of displacement with respect to To time will give you velocity and differentiation of velocity with respect to time will give you acceleration hence you can say double differentiation of displacement will give u acceleration...

so the answer will be

a= 10

Answered by AestheticSky
30

 \maltese \:  \large   \underline{ \pmb{ \sf Correct\: Question :  -  }}

  • What is the acceleration of an object if it's displacement is S = 4t-5t²

 \maltese \:  \large   \underline{ \pmb{ \sf solution :  -  }}

  • First we are going to find the velocity by differentiating the displacement.

  • Then we will differentiate the velocity in order to find the required acceleration.

We know that :-

 \leadsto\large \underline{ \boxed{ \pink{ \sf{velocity =  \frac{dx}{dt} }}}} \bigstar

  : \implies \sf velocity =  \dfrac{d}{dt} (4t - 5 {t}^{2} )

  : \implies \sf velocity = 4 - 2 \times (5t )^{2 - 1}

  : \implies \boxed {\purple{{ \sf velocity = 4 - 10t} }}\bigstar

  • Now, let's find the acceleration by differentiating velocity.

For that :-

 \leadsto\large \underline{ \boxed {\pink{{ \sf accelaration =  \frac{dv}{dt}  }}}} \bigstar

 :  \implies \sf accelaration =  \dfrac{d}{dt} (4 - 10t)

 :  \implies \sf accelaration = 0 - 10 \times (t) ^{1 - 1}

  : \implies  \boxed {\purple{{\sf accelaration =  - 10 \: m {s}^{ - 2} }}} \bigstar

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