Question

what is the acceleration of the block and the trolly system shown in fig. if the coefficient of kinetic friction between blovk and trolly is 0.04 ? what is the tension in the string ?​

Answer 1

Answer:

Function on the trolly is fr=l mr=0.1×20×10

=2 N

Suppose Tension is T then

F.B.D of trolly

Net from =ma

so T−fr=200 cr T−8=20 a−−−−(1)

F.B.D of 3 kg

39−T=3a⇒ 30−T=3a−−−(2)

adding (1) and (2) ⇒a=2322m/s2

Subtraction (2) from (1) we get

T−8(30−T)=20a−3a

⇒ 2T−0=17a=17×2322

⇒  Tension T=27.1Newton