Question

what is the acceleration of two bodies a and b having mass 1kg and 2kg experiencing the same force​

Answer 1

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In this case there is a resistance force in addition to force of gravity acting opposite to the direction of motion. Let the object of 1kg be A and object of 2kg be B. Let the air exert a constant resistance force f (in upward direction) which is same in both cases.

Acceleration of 1 kg object,

[math]a_A = (F-f)/m_A = (m_Ag - f[/math][math])/m_A = g - f/m_A[/math]

Similarly acceleration of 2 kg object,

[math]a_B = g - f/m_B[/math]

Now, [math]m_B > m_A[/math]

Hence, [math]a_B > a_A[/math]

This shows that object B (2 kg) will reach the surface earlier than A (1 kg).

Answer 2

Answer: F= M*A

m1 (mass of a) = 1 kg

m2 (mass of b) = 2 kg

even if the acceleration provided to both the objects is same then also the forces will differ because the masses are different....We can say so because of the equation which we derived from 2nd equation of motion i.e.

Force = Mass*Acceleration