What is the acceleration of velocity v = 2 (X sin X+ cos X) power 1/2?
Answers
Answered by
1
Explanation:
Umm, try differentiating velocity with respect to to time
dv/dt = 2× √XsinX + cosX
= 2× d/dt(y^1/2)
= 2×1/2 × (y^-1/2 × dy/dt) ...... equation 1
y = xcosx + sinx
so dy/dt = dx/dt×cosx + x (-sinx×dx/dt) + cosx × dx/dt
= 2×vcosx - xsinx × v, put this in equation 1
dv/dt = {1/√(xsinx + cosx)}×v{2cosx - xsinx}
Similar questions