Question

What is the acceleration produced by a force of 12 Newton exerted on an object of mass 3kg?​

Answer 1

Using the Newton's Second law of Motion i.e.,

dp/dt = F or F = m(a). Where “F” is the external force applied on the object, “m” is the mass of the object and “a” is the acceleration thus produced.

Given that: F = 12N, m = 3Kg and a = ?

Therefore, using:

F = m(a)

a = F/m = 12/3 = 4 m/s^2

Thus,

Acceleration of the body is = 4 m/s^2.

Answer 2

Answer:

The acceleration produced by the force of 12N exerted on an object of mass 3kg is 4ms⁻².

Explanation:

• According to Newton's second law, a body will accelerate, or change its velocity, at a constant rate, when a constant force is applied to it.

          ∴ Force = Mass × Acceleration ..........(i)

• In the general case, when a force is applied to a stationary object, the object accelerates in the direction of the applied force.
• However, depending on the force's direction and the directions that the object and reference frame are traveling in relation to one another, a body that is already moving or being observed from a moving inertial reference frame may appear to accelerate, decelerate, or change direction.

Given:-

Mass of the object = $3kg$

Force exerted on the object = $12N$

∴ From equation (i), acceleration will be,

Acceleration = Force/Mass

Acceleration = 12/4

Acceleration = $3ms^{-2}$

∴ The acceleration is produced by the force $3ms^{-2}$.

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