What is the acceleration produced by a force of 20N exerted on an object of mass 4kg?
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Explanation:
From F = ma, 20 = 4a so a = 5m/s^2
Now, let’s review the 4 fundamental kinematic equations of motion for constant acceleration (strongly recommend you commit these to memory – they will serve you well):
s = ut + ½at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.
In this case, we know u = 5m/s, a = 5m/s^2, s = 10m, and we want to find v, so we use equation (2):
v^2 = u^2 + 2as
v^2 = 5^2 + 2(5)(10)
v^2 = 125
So, v = √125 = 11.18
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