Question

what is the action of alcoholic ammonia on ethyl bromide​

Answer 1

Answer:

In the first stage, a salt is formed - in this case, ethylammonium bromide. This is just like ammonium bromide, except that one of the hydrogens in the ammonium ion is replaced by an ethyl group. There is then the possibility of a reversible reaction between this salt and excess ammonia in the mixture.

Explanation:

Answer 2

• As an electrophile, ethyl bromine is used.
• Because of the lone pair of electrons on the nitrogen atom, ammonia behaves as a nucleophile.
• Br is a good leaver of the group.
• Second, ammonia works as a base, deprotonating ethylammonium to generate a primary amine, ethylamine, as the end result.

This is straight from the mechanism. The issue is that it only creates the amine salt, not the main amine itself. To account for subsequent substitution processes leading to secondary (and so on) amines, some primary amine must be generated.

The salt of a primary amine and the acid, HBr, is ethylammonium bromide. The formula for a primary amine is R-NH2. It is primary in the sense that the nitrogen atom has only one alkyl group linked to it. Primary amines are weak bases that react with acids to create salts, comparable to ammonia.