Question

What is the action of ammonia on: (a) Acetaldehyde (b) Formaldehyde​

Answer 1

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Here is your Answer: --)

a) Acetaldehyde :--) CH3CHO + 3 NH3 → (CH3CHNH)3 + 3 H2O

b ) Formaldehyde :--) react with ammonia to produce hexamethylenetetraammine and water.

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Answer 2

$4CH_3CHO + NH_3$ → $4H_2O + C_2H_5(C_5H_3N)CH_3$

Explanation:

(1) The action of ammonia on Acetaldehyde -

Acetaldehyde + Ammonia → Water + Phenethylamine

Type  of reaction is Double Displacement reaction .

Reactants  involved are -

• Acetaldehyde $(CH_3CHO)$
• Ammonia $(NH_3)$

Products  formed are -

• Water $(H_2O)$
• Phenethylamine$(C_2H_5(C_5H_3N)CH_3)$

$CH_3CHO + NH_3$ → $H_2O + C_2H_5(C_5H_3N)CH_3$

∴ The balanced chemical equation  is -

$4CH_3CHO + NH_3$ → $4H_2O + C_2H_5(C_5H_3N)CH_3$  

(2) The action of ammonia on Formaldehyde

$HCHO + NH_3$ → $(CH_2)_6N_4 + H_2O$

Reactants  involved are -

• Formaldehyde $(HCHO)$
• Ammonia $(NH_3)$

Products  formed are -

• Hexamethylene-tetra-amine
• Water

∴ The balanced chemical equation  is -

$6HCHO + 4NH_3$ → $(CH_2)_6N_4 + 6H_2O$