What is the action of hot hydroiodic acid on isopr what is the action of hot Android acid on isopropyl Methyl Ether opyl Methyl ether
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The question appears to be asking why it is that if you treat methyl propyl ether with hydrogen iodide, you get four products: methyl iodide, methanol, propyl iodide and propanol.
This is because the reaction is quite indiscriminate.
The mechanism is this: methyl propyl ether protonates at oxygen, and this makes the oxygen a good leaving group for SN2 attack by iodide ion (a good nucleophile).
But you have two possible carbon atoms to react with iodide: the methyl group, and the CH2 of the propyl group. They will react with iodide at similar rates, and so there is no great preference of one over the other.
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