Question

What is the active mass of an ideal gas at 44.8 atm pressure and 0c temperature in mol/lit

Answer 1

Answer:2 mol/lit

Explanation:active mass of gas is equal to its concentration I.e molarity

We need to calculate n/v moles per unit volume

Using the formula PV=nRT

n/V = P/RT

n/V = 44.8/22.4 (RT= 0.0821×273=22.4)

n/V = 2 mol/lit