Question

What is the additive inverse of these rational numbers?
2/3 2) (4/5÷-16/15) 3) x 4) 1/z​

Answer 1

Answer:

$\frac{2}{3} = - \frac{3}{2} \\ \\ \frac{4}{5} \div \frac{ - 16}{15} \\ \frac{4}{5} \times \frac{15}{ - 16} \\ \frac{1}{1} \times \frac{3}{ - 4} \\ = \frac{ - 3}{4} \\ \\ x = \frac{1}{ - x} \\ \\ \frac{1}{z } = \frac{ - z}{1} = > - z$

Answer 2

Answer:

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