what is the algebraic form of even numbers?
a) 2n b) 3n c) 5n d) 2n+1
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Answer:
Option (d) 2n+1 is correct answer.
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Let's a and b are the integers such that a>b
a=bq+r
put the value b=2
a=2q+r
then r =0,1 because r<b
if r=0 then a=2q which are divisible by 2
if r=1 then a=2q+1 which are not divisible by 2
hence all number either in the form of 2q or 2q+1 and we know that these number either be even or odd .
always even number in the form of 2q. plz like
Step-by-step explanation:
hence answer is a.2n
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