Question

what is the amount Al2O3 and Mg required to form 27 g of Al​

Answer 1

Answer:

The balanced equation  for given reaction  is :

4 Al + 3 O2 ⇒ 2 Al2O3

Atomic mass of Al= 27 g

Atomic mass of O2= 2× 16 = 32 g

Mole ratio of aluminium and oxygen can be given as:

Al:O2

4:3

1: 3/4

Mass ofO2 required= 3/4×32=24 g

Explanation: