Math, asked by zirpeshweta, 3 months ago

*What is the amount for Rs. 10000 by compound interest at 8% rate for 2 years?*

1️⃣ ₹ 5000
2️⃣ ₹ 11664
3️⃣ ₹ 15664
4️⃣ ₹ 10664​

Answers

Answered by SachinGupta01
3

Given :

 \sf \: Principal \:  :  \: Rs. \:  10000

 \sf \: Rate  \: of  \: Interest  \: : \:  8 \: \%

 \sf \: Time \:  :  \:  2  \: years

To find :

 \sf \: We  \: have \:  to \:  find  \: the \:  Amount.

So, let's do it :

 \sf \: Formula  \: to  \: find \:  the \:  Amount \:  is :

 \boxed { \sf \: Amount \:  =  \: Principal \bigg(1 \:  +  \:  \dfrac{Rate \: of \: Interest}{100}  \bigg )^{Time} } \: \:

  \sf \longrightarrow \:  Amount \:  =  \: 10000\bigg(1 \:  +  \:  \dfrac{8}{100}  \bigg )^{2}  \: \:

 \sf \: First  \: of  \: all  \: cancel \:  the  \: common \:  factor \:  of   \: 8   \: and  \: 100.

  \sf \longrightarrow \:  10000\bigg(1 \:  +  \:  \dfrac{2}{25}  \bigg )^{2}  \: \:

 \sf \: Now \:  Simplify  \: the \:  expression.

  \sf \longrightarrow \:  10000\bigg( \dfrac{25 \:  +  \: 2}{25}  \bigg )^{2}  \: \:

 \sf \: Now \:  add \:  25  \: and  \: 2.

  \sf \longrightarrow \:  10000\bigg( \dfrac{27}{25}  \bigg )^{2}  \: \:

 \sf \: Again  \: Simplify  \: the \:  expression.

  \sf \longrightarrow \:  10000 \:  \times  \:   \bigg(\dfrac{729}{625}  \bigg)

 \sf \: Here,  \: cancel \:  the \:  common  \: factor \:  of \:  625.

  \sf \longrightarrow \:  16 \:  \times  \: 729

  \sf \longrightarrow \: Multiply  \:  16 \:  by  \: 729.

  \sf \longrightarrow \: 11664 \:  is  \: the  \: Answer..

  \boxed { \sf \longrightarrow \:  Amount \:  =  \: 11664}

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  \sf More \:that\: can \:be\: Solved\: :

  \boxed { \sf \:Comound \: Interest \: =  \:Amount \: - \: Principal}

   \sf \:Comound \: Interest \: =  \: 11664\: - \:  10000

  \boxed { \sf \:Comound \: Interest \: =  \: Rs. \: 1664}

Answered by ParikhAyushi
21

Answer:

Given

Principal=10000

Rate=8%

Time/n=2 years

To find

Amount

\bold\blue{By \ using \ formula \</p><p></p><p> Amount=P(1 \ + \ R/100)^n}

Solution

Amount=\bold\pink{Amount=P(1 \ + \ R/100)^n}

\bold\purple{10000(1 \ + \ 8/100)^2}

\bold\orange{10000(108/100)^2}

\bold\green{10000 \ × \ 108/100 \ × \ 108/100}

\bold\red{108 \ × \ 108}

\bold\blue{11664}

Correct Answer

\bold{option \ 2 \  ₹11664}

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Points to remember

We have use formula Amount=P(1+R/100)^n.

P stands for principal

R stands for Rate

T or n stands for time

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