Question

What is the amount for Rs 10000 by compound interest at 8 %rate for 2 years ​

Answer 1

Answer:

Principal = Rs. 10000; Rate = 2% per half-year; Time = 2 years = 4 half-years.

Amount == Rs. 10824.32.

Rs.[10000*(1+2/100)4]=Rs.[10000*51/50*51/50*51/50*51/50]

C.I. = Rs. (10824.32 - 10000) = Rs. 824.32.

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Answer 2

ANSWER :

THE ANSWER OF THIS PROBLEM IS ₹5832.

SUMMARY:

PRINCIPAL = ₹10000

RATE OF INTEREST = 8 PERCENT COMPOUNDED YEARLY

TIME = 2 YEARS

FORMULA:

A = P[1+R/100]^T

SOLUTION:

A=₹10000[1+8/100]²

A=₹10000×[27/25]²

A=₹10000×729/625

A=₹5832