What is the amount (in g) of hydrogen peroxide (H2O2) needed to make a 6.00 kg , 3.00 % (by mass) H2O2 solution?
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Answered by
26
Answer:
6% H2O2 in water = 6 g H2O2 in 100 mL water = 60 g H2O2 in 1 liter water. ... Therefore the molarity of your 6% solution is 60 g/34 g/mol = 1.765 mol in 1 liter = 1.765 M. To add 10 mmole of H202 to your reaction from this concentration of solution will require 5.67 mL of 6% H2O2.
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Answered by
1
Answer:
180 g of H2O2
Explanation:
3.0 % of 6.00 kg = 3.00/100 * 6.00 kg = 0.18 kg H2O2
0.18 kg = 0.18 kg * 1000 g/kg = 180 g
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