Question

What is the amount, in moles, of sulfate ions in 100 cm3 of 0.020 mol dm3 feso4(aq)?

Answer 1

0.002 moles of $SO_4^{2-}$ are there in $100 cm^3$ of 0.020 $mol/dm^3$ of $FeSO_4$

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$    (1)

Molarity of $FeSO_4$ solution = $0.020mol/dm^3$

Volume of $AgNO_3$ solution = $100cm^3$ = $0.1dm^3$     $1cm^3=0.001dm^3$

Putting values in equation 1, we get:

$\text{Moles of} FeSO_4={0.020mol/dm^3}\times{0.1dm^3}=0.002moles$

$FeSO_4\rightarrow Fe^{2+}+SO_4^{2-}$

1 mole of $FeSO_4$ give 1 mole of $SO_4^{2-}$

Thus 0.002 moles of $FeSO_4$ give =$\frac{1}{1}\times 0.002=0.002moles$ of $SO_4^{2-}$

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