Question

What is the amount of calcium oxide that will react with 852 g of p4o10 ?

Answer 1

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Answer 2

HI DEAR SHRESTA HERE PLS SEE THE ANSWER .....HOPE IT HELPS

WE KNOW THAT

6CaO+P4O10 gives 2Ca3(PO4)2

SO THE GIVEN AMOUNT HERE IS 852g

P4O10 is 31x4+16x10= 248

now divide it to get the no of moles

= 852/248 = 3

so I mole of CaO has 3 then 6 moles of CaO has 6x3= 18

so now we will get 1008 g....