What is the amount of current flowing through 6Ω resistor?
Answers
Explanation:
1
=
R
1
1
+
R
2
1
+
R
3
1
Therefore,
R
total
1
=
3
1
+
6
1
=
0.5
1
=2 Ω.
Hence, their equivalent resistance is 2.4 ohms.
When the circuit is closed, the resulting current not only flows through the external circuit, but through the source (cell) itself. The cell have an internal resistance, which causes an internal voltage drop, slightly reducing the voltage across the terminals. The larger the current, the larger the internal voltage drop, and the lower the terminal voltage.
The current in the circuit is calculated from the formula I=
R+r
ε
where,
ε- emf of the cell
R- external resistance
r- internal resistance of the cell.
When the cell of internal resistance of 3 ohms is connected to the combined resistance of 2 ohms the current is given as:
That is, I=
2+3
15
=
5
15
=3A.
Thus, the current through the circuit is 3 amperes.
The voltage output of a device is measured across its terminals and is called its terminal voltage V. Terminal voltage is given by the equation, V=emf−Ir where, r is the internal resistance and I is the current flowing at the time of the measurement.
It is given that the emf is 15 V and the current is determined to be 3 A.
Thus, the voltage across the terminals of the battery is given as:
V=emf−Ir
V=15V−(3A×3Ω)=6V
The current flowing through the individual resistor(3 ohms) is calculated from the relation I=V/R.
That is, I=
R
V
=
6
6
=1A.
Hence, the current flwoing through the 6 ohms resistor is 1 A.