Chemistry, asked by vidaekugo, 5 months ago

. What is the amount of gold present in 15.5g of a pure gold wedding ring? ( Au = 197)

Answers

Answered by hegde5

8

Answer:

78.68*10-³ mol

Explanation:

Solution

v=m/a

=15.5g

1979/mol

=78.68*10-³mol.

vidaekugo: sorry the rating was a mistake

vidaekugo: thanks for the answer tho

hegde5: ok

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