Question

what is the amount of H2 S o4 required to react completely with hundred litre of NH3 at ntp​

Answer 1

Dear Student,

◆ Answer -

21.86 g of H2SO4 will be required

● Explaination -

At NTP, moles of ammonia are -

n = V / 22.4

n = 10 / 22.4

n = 0.4462 mol

Reaction of H2SO4 with NH3 is represented by -

NH3 + ½ H2SO4 --> ½ (NH4)2SO4

From this 1 mol of NH3 reacts with ½ mol of H2SO4.

Hence, 0.4462 mol of NH3 will react with ½ × 0.4462 = 0.2231 mol of H2SO4.

Mass of H2SO4 required is -

W = 0.2231 × 98

W = 21.86 g

Therefore, 21.86 g of H2SO4 will be required.

Thanks dear. Hope this helps you...

Answer 2

Answer:

the answer is 218.75 g.

Explanation:

the answer is above

hope it helps!

thanks for asking!!!