Question

What is the amount of H2so4 required to react completely with 100 L of NH3(g) at NTP

Answer 1

answer : option (1) 218.75 g

explanation : chemical reaction between NH3 and H2SO4,

2NH3 (g) + H2SO4 (aq) ⇔(NH4)2SO4 (aq)

here, 2 moles of NH3 react with 1 mole of H2SO4 and form one mole of (NH4)2SO4.

at NTP (normal temperature and pressure),

or, 2 × 22.4 L of NH3 reacts with 98g of H2SO4 and form one mole of (NH4)2SO4.

or, 44.8L of NH3 = 98g of H2SO4

or, 1L of NH3 = 98/44.8 g of H2SO4

or, 100L of NH3 = 9800/44.8 g of H2SO4

= 218.75 g of H2SO4.

hence, option (1) is correct choice.

Answer 2

Answer:

here

Explanation:

explanation in attachment.....refer to pic