Question

What is the amount of HCl required to completely react with 200g of CaCO3 according to the equation CaCO3+2HCl--->CaCl2+CO2+H2O

Answer 1

For us to work out this question, we need to get the mole ratio from the equation above.

The mole ratio is: 1 :2

That is for every mole of calcium carbonate reacting, there are two moles of HCl reacting.

Molar mass of calcium carbonate :

40(calcium) + 16(oxygen) ×3 + 12(carbon)=100g

100g=1mole

200g=?

200/100 ×1= 2moles.

USING MOLE RATIO TO GET REACTING MOLES OF HCl:

Molar mass of HCl=35.5(Chlorine) + 1(Hydrogen)=36.5g

Mole ratio=1:2

Moles of HCl reacting=2×2=4moles

1 mole=36.5g

4moles =?

4×36.5=146grams

The mass of HCl reacting with 200g of calcium carbonate is 146 grams.

Answer 2

Answer:

146 grams

Explanation:

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