What is the amount of heat necessary to raise the temperature of 8.5 kg of water from 12.5 °C to 84 °C?
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Answer:
2.55×10^6J
Explanation:
ΔQ=mcΔT
m=8.5kg
ΔT=84-12.5=71.5°C or 71.5K
c(heat capacity of water) = 4200J/kg
ΔQ=8.5×4200×71.5=2.55×10^6J
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