what is the amount of heat needed to melt 2 kg of ice at its melting point when the latent heat of ice is 80 cal/g. (1 cal = 4.184J)
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Answer:669.4KJ
Explanation:
2Kg=2000g
Heat= m×∆H
=2000×80
=160000cal
1 Cal=4.184J
Heat=160000×4.184
=669440J
=669.44KJ
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