Question

what is the amount of inertia of a road of mass m,length L about an axis perpendicular to it through one end?​

Answer 1

Answer:

=4ML²/12 = ML²/3

Explanation:

Here we can use parallel axis theorem.

as you know that moment of inertia of a rod about centre of mass is ML²/12

then from centre of mass to one end distance =L/2  then, moment of inertia at any end of rod=[ML²/12]+[M(L/2)²]

=(ML²/12)+(ML²/4)

=4ML²/12 = ML²/3

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