What is the amount of work done in moving a 200 mucoulomb charge between 5 CM apart on an equipotential surface?
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Answer:
0J work is done
Explanation:
Work done on a charged body placed in an electric field is calculated as the potential difference
If a unit charge is moved from point A to point B the work done against the field will be the potential difference between the points A and B
Work Done = Potential at A - Potential at B
In the given case,
q = 200 μC
d = 5cm
Since the given surface is an equipotential surface,
Potential at A = Potential at B = V
Therefore,
Work done = Potential at A - Potential at B
W = V - V
W = 0J
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