Question

What is the amount of work done in moving a 200 mucoulomb charge between 5 CM apart on an equipotential surface?

Answer 1

Answer:

0J work is done

Explanation:

Work done on a charged body placed in an electric field is calculated as the potential difference

If a unit charge is moved from point A to point B the work done against the field will be the potential difference between the points A and B

Work Done = Potential at A - Potential at B

In the given case,

q = 200 μC

d = 5cm

Since the given surface is an equipotential surface,

Potential at A = Potential at B = V

Therefore,

Work done = Potential at A - Potential at B

W = V - V

W = 0J