Question

What is the amount of work done in moving a charge of 10nc between two points separated by a distance of 5cm on a surface having same potential of 50v?

Answer 1

The amount of work done...
= charge×potential difference

Here charge =10nC=10^-8C
and potential difference=0

So.......

W=10^-8×0
W=0J

Answer 2

HEY MATE

HERE IS UR ANS

AS POTENTIAL DIFFERENCE =WORK /CHARGE

V=W/Q

Here Q=10nc =10^-8

V=50

so W=V×Q

W=50 ×10^-8

=50×10-7J

Hope it helps u dear

ße ßrainly....⛤⛤⛤