Question

What is the amount of work done when 0.5 mole of methane, CH4(g), is subjected to combustion at 300K? (given, R = 8.314JK-1 mol-1​

Answer 1

Answer:

The amount of work done is 1.2471 kJ.

Explanation:

Work done by the when the 0.5 mol of methane was subjected  to combustion at 300 K.

Work done = Pressure × Volume =PV

Using ideal gas equation:

$PV=nRT$

$PV=0.5 mol\times 8.314 J/K mol \times 300 K=1,247.1 J=1.2471 kJ$

The amount of work done is 1.2471 kJ.