Question

What is the amount of work done when 2 moles of ideal gas is compressed to form 1m3to 10dm3 at 300k against the pressure of 100KPa

Answer 1

Answer:

HEYY MATE...

M=2 moles

=2×6.022×10^23

G1=1m^3

G2=10dm^3=10×10^-3

P1=300K

P2=100K

W1=1×2×6.033×10^23÷300

W2=10×10^-3×6.022×10^23÷100

Now from here u can find work done.

HOPE IT HELPS U...

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Answer 2

Refer to the attachment!!!