What is the angle at a center of a circle if the subtending chord is equal to two thirds of the radius?
a. 39.95deg
b. 38.94deg
c. 37.93deg
d. 36.92deg
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Answer:
Given: A circle with center O.
AB and CD are equal chords of the circle.
Proof:In △AOB and △DOC
AO=OD (radius)
AB=CD (given)
OB=OC(radius)
∴△AOB≅△DOC by SSS rule
∴∠AOB=∠DOC by CPCT
Hence proved.
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