What is the angle between A i j k, B 2i 2 j 2k.
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a=i+2j-k
b=-i+j-2k
as we know that,for two given vectors a
and b,we have:-
a.b=lal*Ibl*cos a^b
where a^b is the angle between the
vectors a and b
so, a.b= 1*-1+2*1+-1*2=3
lal=(1+4+1)^1/2=V6
Ibl=(1+1+4) 1/2=V6
from the given equation,we have
3=16*16*cos a^b
So,cos a^b=3/6=1/2
so angle between the vectors is 60
degree
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