What is the angle between A vector=5i-5j and B vector=7/2i-7/2j
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GivEn:
- Ā = 5i - 5j
- B = 7/2i - 7/2j
To find:
- The angle between them?
Solution:
In order to calculate the angle between them, We have to use,
★ Cos theta = A . B/|A||B|
Here,
- A . B = Dot product of A bar & B Bar.
- |A||B| = Mod of A & B.
⠀━━━━━━━━━━━━━━━━━━━━━━━━━━
« By applying it,
⇒5(7/2) + 5(-7/2)/|A||B|
⇒– 24.5 + 24.5/|A||B|
⇒(0)/(√5² + 5²√7/2² + 7/2²)
⇒(0)/(√50√24.5)
⇒0/35
⇒Cos θ = 0°
⇒θ = Cos^-1 0°
⇒θ = 90°
∴ Hence, The angle between the two vectors is 90°.
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